如何确定一组数据服从什么分布?

如何确定一组数据服从什么分布?
数据如下：
416,782,674,1121,5,1277,1033,1167,1136,1296,1084,191,343,141,2108,720,92,351,1371,281,1589,1190,412,779,713,1767,142,228,170,313,2272,2068,1252,547,864,917,745,1812,2237,866,739,213,1062,1534,1253,715,166,1304,637,1802,1538,414,1951,787,2216,59,1382,1503,831,501,1060,2205,1544,968,758,1126,845,745,120,1507,200,1278,1361,1619,1168,1234,298,1366,1931,252,1195,1875,793,1646,1583,1892,1477,1177,922,2098,1671,1648,2039,1431,15,1060,1774,1649,1473,1920,1002,1089,1551,713,80,760,1440,716,1301,269,359,1372,2106,1256,161,683,1546,1478,1676,1398,1126,1026,1964,383,1602,1217,960,1515,611,700,1099,900,1095,2203,1248,1133,974,794,2178,1318,443,29,825,1773,174,1120,1025,310,1370,633,2159,339,1039,940,1520,770,1765,1029,2554,541,379,740,1063,1755,276,680,1450,1475,1115,990,1091,47,420,1984,1226,1486,1421,1137,21,1488,1518,307,970,810,688,12,16,483,1246,1412,1131,477,1396,182,2018,2072,640,1027,926,451,1193,1513,201,263,1409,729,1340,205,1520,1484,837,1059,147,1663,1787,1671,437,1399,1373,876,1644,1678,558,1138,1693,1638,579,1638,2141,1464,254,502,1312,1202,643,1332,1408,1521,1299,1390,58,905,204,864,579,946,312,748,1055,844,909,167,2311,711,1238,1267,821,608,686,2174,229,1457,108,2351,947,397,812,803,62,2298,720,2401,1220,628,947,779,1195,995,2158,1477,1062,1127,757,1095,1488,2128,1162,1321,1072,1023,342,1179,1103,977,1154,457,79,828,1098,1861,451,164,679,2391,1281,429,369,1023,2310,421,106,893,666,2322,216,371,106,1110,716,608,331,191,491,1469,1040,703,695,1045,639,689,504
如果确定这组数据属于那种分布?怎么把它化为正态分布?
天才庆鑫 能具体说一下是怎么算出来的吗？

正态分布
平均值1035.2,置信区间(1033.2,1037.3)
方差595.5501,置信区间(594.6990,597.6117)
用MATLAB画出分布直方图,估计为正态分布；
求法：设上述数据为向量X；
选取“取伪”错误的概率a=0.01；
利用Jarque-Bera检验原则校验数据正态分布的合理性；
命令为：jbtest(X,0.01)
得到结果为0,说明数据基本符合正态分布要求；
利用正态分布拟合函数求正态分布基本参数：
[u,o,Au,Ao]=normfit(X,0.01)
得到平均值u,平均值置信区间Au,方差o,方差置信区间Ao.
呵呵!不知这样行不行啊?