3a+2b=3,则8-6a-4b=__
3a+2b=3,则8-6a-4b=__
定义新运算a&b=2a+b,a@b=a×b×b,则4&(3@2)=__
集合A{x|x-6x+8<0},集合B={x|a<x<3a},若A是B的真子集,则a的取值范围__拜托各位大神
已知|a|=-a,b<0,化简|2a+6b|/(a+3b)^2-6/|a+3b|-2/|2b+3-|a+b-3||为__
如果a-2b/a+2b=3,求a+2b/a-2b+3a-6b/4a+8b
(a-2b)/(a+2b)=3,求(a+2b)/(a-2b)+(3a-6b)/(4a+8b)的解,
(a+2b)(2a+4b)(3a+6b)(4a+8b)
3a^2b-{2a^2b+[9a^b-(6a^2b+4a^2)]-(3a^2b-8a^2)}=
a+b分之3a-6b-a-b分之5a-6b-a+b分之4a-5b-b-a分之7a-8b
a-2b/a+2b=3,求2+2b/a-2b+3a-6b/4a+8b的值
(3a-6b)/(a+b) - (5a-6b)/(a-b) - (4a-5b)/(a+b) - (7a-8b)/(a-b
(3a-6b/a+b)-(5a-6b/a-b)-(4a-5b/a+b)-(7a-8b/b-a)