cosx^2=1+cosx/2还是等于1+cos2x/2?还有sin2x=1-cosx吗?
cosx^2=1+cosx/2还是等于1+cos2x/2?还有sin2x=1-cosx吗?
求证:(1-2sinx×cosx)/cos2x-sin2x=(cos2x-sin2x)/(1+2sinx×cosx)
已知sinx=-1/2cosx,cosx-sinx/cosx+sinx+sin2x+cos2x的值
(1+cos2x)/2cosx=sin2x/(1-cos2x)
Cosx+sinx分之1+sin2x+cos2x=2cos 证明
已知函数f(x)=(sin2x+cos2x+1)/2cosx,
(cos2x-sin2x)/[(1-cos2x)(1-tan2x)] =cos2x/(1-cos2x)=[cosx)^2
求证:(sin2x / 1+cos2x) ×(cosx / 1+cosx) =tan(x/2)
已知2sin2x-cos2x+sinxcosx-6sinx+3cosx=0,求2cosx(sinx+cosx)1+tan
怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
(sinx^2+sin2x)/(cosx^2=cos2x)等于多少
cos2x+sin2x=1 那么sinx-cosx等于多少