证1/a+1/b+1/c≥2/(a+b)+2/(b+c)+2/(a+c)
1.计算:(1)(a-b)(a-c)分之2a-b-c + (b-c)(b-a)分之2b-c-a + (c-b)(c-a)
1、化简:| b-c |+| a-b |-| a+c | 2、化简:2c+|a+b|+
证1/a+1/b+1/c≥2/(a+b)+2/(b+c)+2/(a+c)
A=B+B+B+B+B+B+B+B+B+B+B+B+B+B+B A-B×3=C C+2×7+2=1
..a b c为正,求证a^2/(b+c)+b^2/(c+a)+c^2/(a+b)>=1/2(a+b+c)
已知a,b,c是正实数,满足a^2=b(b+c),b^2=c(c+a).证明:1/a+1/b=1/c
柯西不等式证(a+b+c)*(1/a+b+1/a+c+1/b+c)大于等于9/2
设a+b+c,b+c-a,c+a-b,a+b-c成G.P,公比为a/c,试证r^3+r^2+r=1
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(
行列式证明|b+c c+a a+b| | a b c||a+b b+c c+a| = 2 |c a b||c+a a+b
设a、b、c均为正实数,求证:1/2a+1/2b+1/2c≥1/(b+c)+1/(c+a)+1/(a+b)
若a,b,c属于正实数,求证:1/2a+1/2b+1/2c≥1/(b+c)+1/(a+c)+1/(a+b)