2lg5+(lg2)^3*(2lg5+lg2)计算~

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/10 14:40:04

设x=lg5,lg2=1-lg5=1-x
2x+(1-x)^3(1+x)
=2x+(1-x)^2(1-x^2)
=2x+(x^2-2x+1)(1-x^2)
=2x+x^2-x^4-2x+2x^3+1-x^2
=-x^4+2x^3+1
=x^3(2-x)+1
=(lg5)^3*lg20+1
好像只能化到这了,不知道了.

计算：(lg5)^2 +lg2 *lg5 计算 lg5^2+lg2*lg5+lg2 lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5 2lg5+(lg2)^3*(2lg5+lg2)计算~ 3+lg5+(lg2)^2 计算(lg5)^2+lg4*lg5+(lg2)^2 计算：1. (lg5)^2 +lg2 *lg5 计算(lg2)^2+(lg5)^2+2lg2*lg5 计算(lg2)²+(lg5)²+2lg2*lg5 (lg5)^2+lg5.lg2= lg2(1+lg5)+(lg5)^2 (lg2)^2+lg2*lg5+(lg5)^2=