#include int b=2; int fun(int*k) { b=*k+b;return(b);} main()
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#include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}
#include
int b=2;
int fun(int*k)
{ b=*k+b;return(b);}
main()
{int a[10]={1,2,3,4,5,6,7,8},i;
for(i=2;i
#include
int b=2;
int fun(int*k)
{ b=*k+b;return(b);}
main()
{int a[10]={1,2,3,4,5,6,7,8},i;
for(i=2;i
循环2次,输出10,28
fun()函数求b(2)与传入参数的和.实际调用就是你数组第三个元素与第四个
i = 2;fun(&3)过后,b = 5;5+5 = 10;此时b = 10;
i = 3;fun(&4)过后,b = 14;14+14 = 28;此时b = 28
fun()函数求b(2)与传入参数的和.实际调用就是你数组第三个元素与第四个
i = 2;fun(&3)过后,b = 5;5+5 = 10;此时b = 10;
i = 3;fun(&4)过后,b = 14;14+14 = 28;此时b = 28
#include int b=2; int fun(int *k) {b=*k+b;return(b);} main()
#include int b=2; int fun(int*k) { b=*k+b;return(b);} main()
int b=2;int fun(int*k) {b=*k=b;return (b);} main() {int a[10
#include"stdio.h" fun(int k,int *p) {int a,b;if(k==1||k==2)*
#include int b=3; int fun(int *a) { b+=*a; return(b); }
#include func(int a,int b) {int c; c=a+b; return c;} main()
#include void fun(int a,int b) {int t; t=a;a=b;b=t; } main()
#include int func(int a,int b) { int c; c=a+b;return c; } ma
有如下程序 int runc(int a,int b) { return(a+b);} main( ) { int x=
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c;
#include int fun(inta,intb,intc) {c=a*b} main() {intc; fun(2
#include #include // void fun(int a,int b,int c