已知x>0,y>0且x-2根号下xy-15y=0,则2x+根号下xy+3y除以x+根号下xy-y=?

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/11 14:04:36

已知x>0,y>0且x-2根号下xy-15y=0,则2x+根号下xy+3y除以x+根号下xy-y=?
麻烦了星期1交

x-2根号xy-15y=0
(根号x-5根号y)*(根号x+3根号y)=0
所以(根号x-5根号y)=0,(根号x+3根号y)=0
得：根号x=5根号y,根号x=-3根号y（舍去）
x=25y
将之代入所求式子得：
2x+根号xy+3y/x+根号xy-y
=[2*25y+根号（25y*y）+3y]/[25y+根号（25y*y）-y]
=（50y+5y+3y）/(25y+5y-y)
=58y/29y
=2

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