作业帮分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/06/06 07:27:47
分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
{[(x²-4)/(x²-4x+4)]-(x-2)/(x+2)}/[x/(x-2)]
=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)][(x-2)/x]-[(x-2)/(x+2)][(x-2)/x]
=(x+2)/x-(x-2)²/x(x+2)
=[(x+2)²-(x-2)²]/x(x+2)
=[(x+2)-(x-2)][(x+2)+(x-2)]/x(x+2)
=8x/x(x+2)
=8/(x+2)
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再问： {[(x²-4)/(x²-4x+4)]+(2-x)/(x+2)}/[x/(x-2)]
=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)][(x-2)/x]-[(x-2)/(x+2)][(x-2)/x]
=(x+2)/x-(x-2)²/x(x+2)
=[(x+2)²-(x-2)²]/x(x+2)
=[(x+2)-(x-2)][(x+2)+(x-2)]/x(x+2)
=8x/x(x+2)
=8/(x+2)
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮,谢
再问： {[(x²-4)/(x²-4x+4)]+(2-x)/(x+2)}/[x/(x-2)]
分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
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