作业帮将[(X+3/X^2-4)-(-X/6-X-X^2)]/[1-(X^2-3X-15)/(X^2+X-6)]化简
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/06 03:47:46
将[(X+3/X^2-4)-(-X/6-X-X^2)]/[1-(X^2-3X-15)/(X^2+X-6)]化简
[(X+3)/(X^2-4)-(-X)/(6-X-X^2)]/[1-(X^2-3X-15)/(X^2+X-6)]
={(x+3)/[(x+2)(x-2)]-x/[(x+2)(x-3)]}/[(4x+9)/(x+2)(x-3)]
={(x+3)(x-3)/[(x+2)(x-2)(x-3)]-x(x-2)/[(x+2)(x-2)(x-3)]}*(x+2)(x-3)/(4x+9)
=(2x-9)/[(x+2)(x-2)(x-3)]*(x+2)(x-3)/(4x+9)
=(2x-9)/[(x-2)(4x+9)]
={(x+3)/[(x+2)(x-2)]-x/[(x+2)(x-3)]}/[(4x+9)/(x+2)(x-3)]
={(x+3)(x-3)/[(x+2)(x-2)(x-3)]-x(x-2)/[(x+2)(x-2)(x-3)]}*(x+2)(x-3)/(4x+9)
=(2x-9)/[(x+2)(x-2)(x-3)]*(x+2)(x-3)/(4x+9)
=(2x-9)/[(x-2)(4x+9)]
已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值
将[(X+3/X^2-4)-(-X/6-X-X^2)]/[1-(X^2-3X-15)/(X^2+X-6)]化简
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
约分 (X的平方+4x+3)(2x-x)^/(X^+X)(X^+X-6),
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
2x+3x+4x+5x+x+6x+7x=100
x/x-3-5x/x^2-x-6计算