sin3xsinx)为什么等于1/2(cos2x-cos4x)?
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/18 15:29:07
sin3xsinx)为什么等于1/2(cos2x-cos4x)?
sin3xsinx
=sin(x+2x)sinx
=(sinxcos2x+cosxsin2x)sinx
=sin²xcos2x+sinxcosxsin2x
=(1/2)(1-cos2x)cos2x+(1/2)sin²2x
=(1/2)cos2x-(1/2)cos²2x+(1/4)(1-cos4x)
=(1/2)cos2x-(1/4)(1+cos4x)+1/4-(1/4)cos4x
=(1/2)cos2x-1/4-(1/4)cos4x+1/4-(1/4)cos4x
=(1/2)cos2x-(1/2)cos4x
=(1/2)(cos2x-cox4x)
=sin(x+2x)sinx
=(sinxcos2x+cosxsin2x)sinx
=sin²xcos2x+sinxcosxsin2x
=(1/2)(1-cos2x)cos2x+(1/2)sin²2x
=(1/2)cos2x-(1/2)cos²2x+(1/4)(1-cos4x)
=(1/2)cos2x-(1/4)(1+cos4x)+1/4-(1/4)cos4x
=(1/2)cos2x-1/4-(1/4)cos4x+1/4-(1/4)cos4x
=(1/2)cos2x-(1/2)cos4x
=(1/2)(cos2x-cox4x)
求证(sin4x)/(1+cos4x)*(cos2x)/(1+cos2x)*(cosx)/(1+cos)=tanx/2
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