若(x²+y²)(x²-1+y²)-12=0,求x²+y²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
已知x²+y²-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
x²+y²-6x+8y+25=0求(x-y)-²
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
2x²-3xy=y²=0(x,y不得o)求x/y+y/x
已知(x²+y²)(x²-1+y²)-12=0,求x²+y²
若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值
若(x+y)²-2x-2y+1=0,求(x+y)的999次方
若4x²-4x+9y²-12y+5=0,求(x-3y)²-(x+3y)²