y=a(x-m)^2-a(x-m)怎样转换成y=(x-m-1/2)^2-a/4
已知a^m=1/2x+2y;a^m+1=1/4x²+4y²-xy,求a^2m+1
已知m(a)、M(a)分别是函数y=x^2-ax+a/2(a
已知集合M={x||x+1|≤1} P={y|y=4^x-a*2^(x+1)+1 x∈M}
若[-3(x+y)^m*(x-y)^2n]^2*[-(x+y)^2]=-a(x+y)^10*(x-y)^12-n,求m,
已知圆C:(x+2a)^2+(y-a)^2=9,直线l:(m+2)x+(1-m)y+m-4=0,
设A={(x,y)|y=-2x+3,x,y∈R},B={(x,y)|y=(4m-3{m}^{2})x+1,x,y∈R},
设M=(a/a=x^2-y^2,x,y属于Z),求证:
设集合A={y|y=x²+2x-3,x∈[-2,2]},B={x|(x-m-1)(x-2m+1)
已知a*(x^3y^4)^3/(1/6x^2+ny^4)=3/4x^2y^2m,求实数a,m,n的值
已知抛物线y=x^2-4x+m的顶点A在直线y=-4x+1上
集合M={(x,y)|x^2+2x+y^2=x+a},且M交N=M,求a的取值范围.
已知集合m={(x,y)/x平方+2x+y=0},n={(x,y)/y=x+a},且空集是m交n