有关加速运动An airplane accelerates from a velocity of 21m/s at a

来源：学生作业帮编辑：作业帮分类：英语作业时间：2024/05/27 00:53:23

有关加速运动
An airplane accelerates from a velocity of 21m/s at a constant rate of 3.0m/s² over 535m.what is the final velocity?
The pilot stops the same plane in 484m using a constant acceleration of -8.0m/s².How fast was the plane moving before braking began?
其中accelerates是加速的意思
velocity是速率
constant是持续不变的
rate是速度

1
设最终末速度为v

根据公式v2^2- v1^2=2as(a代表加速度,s代表位移,v1代表初速度,v2代表末速度）

得到v^2-21^2=2x535x3

解次方程得到v约等于60.4m/s
2
这个题跟上面的题有些类似设初速度为v0,末速度为0

根据上题使用的公式

v2^2-v1^2=2as(a代表加速度,s代表位移,v1代表初速度,v2代表末速度）

得到方程：0-v0^2=2x（-8）x484

解次方程得到v0=88m/s

以上即为所求

希望对你有帮助,请给分!谢谢!

译文的意思是
1.飞机从21m/s开始以3m/s^2加速,飞行了535m,求末速度
2.飞机以飞行中以-8m/s^2减速,飞行了484米后停止,就初始速度.

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