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(x-1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/23 13:35:55
(x-1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)
题目抄错了、是(x+1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)!!!!!
(x-1)/(x²+3x+2)+(x+3)/(x²+7x+12)
=(x-1)/(x+1)(x+2)+(x+3)/(x+3)(x+4)
=(x-1)/(x+1)(x+2)+1/(x+4)
楼主没抄错题么?
再问: 好吧。真抄错了、是(x+1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)
再答: (x+1)/(x²+3x+2)+(x+3)/(x²+7x+12) =(x+1)/(x+1)(x+2)+(x+3)/(x+3)(x+4) =(x+1)/(x+1)(x+2)+1/(x+4) =1/(x+2)+1/(x+4) =(x+4)+(x+2)/(x+2)(x+4) =(x²+2x+4x+8)/(x+2)(x+4) =(x²+6x+8)/(x+2)(x+4) =(x+2)(x+4)/(x+2)(x+4) =1