g(x)=sin^2(x)+cos^2(x)和f(x)=1有什么不同?
设f(x)=sin兀x(x=0),g(x)=cos兀x(x=1/2)
设x∈【0,π/2】,f(x)=sin(cosx),g(x)=cos(sinx),把0,1,f(x)的最大值和g(x)的
已知函数f(x)=cos(2x-π/3)+sin^2x-cos^2x,设函数g(x)=[f(x)]^2+f(x),求g(
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x).
已知函数f(x)=cos^x-sin^x/2,g(x)=1/2sin2x-1/4
已知f(x)=sin(x/2) + cos(x/2) +[cos(x/2)]^2-1/2
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1
已知函数f(x)=2Cos x(Sin x-Cos x)+1
f(x)为奇函数,x>0,f(x)=sin 2x+cos x,则x
已知函数f (X)=cos x -sin x /2,g (x )=1/2sin 2x -1/4.
已知函数f(x)=2sin(x/4)cos(x/4)-2√3sin²(x/4)+√3,且g(x)=f(x+π/