(1)、2(x-7)²-18=0(2)、4(x+3)²=144
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
x²+3x-1=0,1/(x-2)×(x²-4x+4)/(x+1)-(x-1)/(x+2)
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
解方程①(x+3/x-1)²-5(x+3/x-1)+6=0 ②x²-2/x+3-6x+18/x
先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2
因式分解 (1) x³-3x²+4x=0 (2) x³+5x+18=0 (3) (6x+7
3X+(X+2)+(X+1)*(X-1)=4*(X²+8)
x²-4x+1=0 3(x-2)²=(x-2)
f(x)=x²+3x|x-2|
3x(x²+2x²+1)-x(x-2)(2x+4)=?
7x²-4x-3=0 -x²-x+12=0 x²-6x+9=0 (3x-2)²=
已知x²+8x-13=0,求(x+2)(x-2)-4x(x-1)+(2x+1)²的值