AB=AC AD=AE ∠BAE=∠CAD 求证;BD=CE.
如图,AB=AC,AD=AE,BD=CE.(1)若AD⊥AE,求证:BD⊥CE;(2)若BD⊥CE,求证:∠BAE+∠C
已知:如图.AB=AC,AE=AD,BD=EC,求证:∠BAE=∠DAC
已知,如图,AB=AC,AD=AE,BD=CE,AC平分DE.求证:(1)∠BAC=∠DAE;(2)∠BAD=∠CAD.
已知,如图,AB=AC,AD=AE.BD=CE,AC平分DE.求证∠BAD=∠CAD
E是四边形ABCD的对角线BD上一点,且AB/AE=AC/AD,∠BAE=∠CAD,是说明∠ABC=∠AED
如图,△ABC中,AB=AE,AC=AD,∠BAE=∠CAD=90°,求证:△ABC与△EAD的面积相等
如图,△ABC中,AB=AE,AC=AD,∠BAE=∠CAD=90°.求证;△ABC与△EAD的面积相等
如图,已知AB=AC,AD⊥AC,BD⊥AD,CE⊥AE,AC平分∠BAE,若以BD,EC,AB为边能画一个三角形吗,请
问一道初二数学题17如图,AB=AC,AD=AE.BD=CE①若AD⊥ AE,求证BD⊥ CE②若BD⊥ CE,求证∠B
如图,已知AB=AC,AD=AE,BD=CE,求证:∠3=∠1+∠2
已知:如图所示,AB=AC,BD=CE,AD=AE,求证∠BAC=∠DAE
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE