(1)4x∧4-65x²y²+16y∧4
因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(x-2y)²+(2x-4y)(x+y)+(x+y)²
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
3(x-y)²×[-4/15(y-x)³][-3/2(x-y)∧4]
因式分解:25(x+y)²-9(x-y)²;(x+y)²-4(x+y-1).
(x+y)²+4(x+y)-5
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
(3x-y)²-2x(4x-5y)-(x+2y)²