(2sinA2+sin2A)/1+tanA(帮忙化简
化简sin2a(1+tana*tana/2)
化简根号sin2a(1+cota)+cos2a(1+tana)
1-cos2a+sin2a/1+tana怎么化简
求证:2(sin2a+1)/(1+sin2a+cos2a)=tana+1
证明 2(sin2a+1)/1+sin2a+cos2a=tana+1
1+tan^2a/tana如何化简为2/sin2a?
1.化简[2sin2a/(1+cos2a)]*1/tana
化简(2sin^2a+sin2a)/(1+tana)
已知tanA=2 求1/(sin2A)过程
已知2sin2a+1=cos2a,求tana的值
已知(2sin^a+sin2a)/(1+tana)=k (0
证明:(sin2a+1)/(sin2a+cos2a+1)=1/2(tana+1)