已知,如图,AB⊥AC,AB=AC,AD⊥'AE,AD=AE,求证:(1)BE=CD;(2)BC⊥CD
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD
已知如图,AB=AC,∠1=∠2,AD⊥CD,AE⊥BE,求证:AD=AE
如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF
如图AB=AC AD=AE,BE与CD相交于点o,求证AO⊥BC
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
如图,已知AB垂直AC,AD垂直AE,AB=AC,AD=AE,求证BE=CD且BE垂直CD.图在后面.
如图,已知AE⊥AD,AF⊥AB,AB∥CD,AF=CD,AE=AD,求证:AC垂直EF.
如图,AB=AC,CD⊥AB于D,BE⊥AC于E,BE与CD相交于点O (1)求证AD=AE; (2)连接OA,BC,试
如图 AB=AC,CD⊥AB于D,BE⊥AC于E,BE与CD相交于点O. (1)求证AD=AE; (2)连接OA,BC,
已知AD⊥AB,AC⊥AE,且AD=AB,AC=AE,CD分别交AB,BE于点G,F 求证1)∠B=∠C 2)BE⊥CD
已知:如图,CD,BE是三角形ABC的高.求证:(1).AD:AC=AE:AB (2).角AED
已知:如图,AB=AC,BE⊥AC ,CD⊥AB,垂足分别为E,D.求证:AD=AE