若a2=3a-1，则分式2a

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/19 19:14:54

若a²=3a-1，则分式

原式=
2a3(a2+1)-a2(5a2+8)
a2+1
=
2a3(3a-1 +1)-a2[5(3a-1)+8]
a2+1
=
2a3•3a-a2[15a+3]
a2+1
=
6(3a-1)2-(3a-1)[15a+3]
a2+1
=
(3a-1)[6(3a-1)-(15a+3)]
a2+1
=
(3a-1)(3a-9)
a2+1
=
9(3a-1)-30a+9
3a
=
-3a
3a
=-1．
故答案为：-1．

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