a1=1 an+1=an+2n 求an解析式 要过程,大谢

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. a1=1/2,an+1=an/an+2,求n/an的sn 数列{an}中,a1=35,an+1-an=2n-1,求an 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 已知A1=1,An=2An-1+n（n>1）,求An. 设数列{an}中,a1=2,a(n+1)=an+n+1,求an “在等比数列｛an｝中,a1+an=66,a2*an-1=128,求n及公比q"这个问题的过程A2*An-1=A1*An 数列an,a1=4,an+1=5^n*an,求an 已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an 数列{an}满足a1=1,an=3n+2an-1(n≥2)求an 已知等比数列{an}中有an+1-an=n×2^n且a1=1求an