f(x,x)=x f(x,y)=f(y,x) (x+y)f(x,y)=yf(x,x+y)求f(14,52)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/23 22:43:44
f(x,x)=x f(x,y)=f(y,x) (x+y)f(x,y)=yf(x,x+y)求f(14,52)
由题知,
f(x,x)=x f(x,y)=f(y,x) (x+y)f(x,y)=yf(x,x+y)
所以,
f(14,52)
=f(14,14+38)
=(52/38)f(14,38)
=(52/38)f(14,14+24)
=(52/38)(38/24)f(14,24)
=(52/24)f(14,14+10)
=(52/24)(24/10)f(14,10)
=(52/10)f(10,14)
=(52/10)f(10,10+4)
=(52/10)(14/4)f(10,4)
=(52/10)(14/4)f(4,10)
=(52/10)(14/4)f(4,4+6)
=(52/10)(14/4)(10/6)f(4,6)
=(52/10)(14/4)(10/6)f(4,4+2)
=(52/10)(14/4)(10/6)(6/2)f(4,2)
=(52/10)(14/4)(10/2)f(2,4)
=(52/2)(14/4)f(2,2+2)
=(52/2)(14/4)(4/2)f(2,2)
=(52/2)(14/4)(4/2)*2
=26*14
=364
f(x,x)=x f(x,y)=f(y,x) (x+y)f(x,y)=yf(x,x+y)
所以,
f(14,52)
=f(14,14+38)
=(52/38)f(14,38)
=(52/38)f(14,14+24)
=(52/38)(38/24)f(14,24)
=(52/24)f(14,14+10)
=(52/24)(24/10)f(14,10)
=(52/10)f(10,14)
=(52/10)f(10,10+4)
=(52/10)(14/4)f(10,4)
=(52/10)(14/4)f(4,10)
=(52/10)(14/4)f(4,4+6)
=(52/10)(14/4)(10/6)f(4,6)
=(52/10)(14/4)(10/6)f(4,4+2)
=(52/10)(14/4)(10/6)(6/2)f(4,2)
=(52/10)(14/4)(10/2)f(2,4)
=(52/2)(14/4)f(2,2+2)
=(52/2)(14/4)(4/2)f(2,2)
=(52/2)(14/4)(4/2)*2
=26*14
=364
f(xy)=xf(y)+yf(x) 求f(x)
二元函数f(x,y)=x+y/x-y,求f(y/x,x/y)
f(xy)=f(x)+f(y),证明f(x/y)=f(x)-f(y)
设函数f(x)对一切实数x,y满足f(xy)=xf(y)+yf(x)-xy且|f(x)-x|≤1,求函数f(x).
高等数学f(x+y)=f(x)+f(y)/1-f(x)f(y),求f(x)
f(x+y)=f(x)*f(y)说明什么?
f(x+y)=f(x)+f(y)是什么意思.
y=f(f(f(x))) 求导
f(x+y)=f(x)f(y)且,x>0,f(x)属于(0,1)
设f(u)具有二阶连续导数,且g(x,y)=f(y/x)+yf(x/y),求x²(δ²g/δx&su
高数:已知f(x+y,y)=x^2+y^2,求f(x,y)
y=f(x+sinx) 求y''.