蟹蟹!2.如图,已知AB⊥BC,AE⊥ED,AB=BC,∠DCE=135°,说明AE=ED
如图,已知AB垂直于BC,AE垂直于ED,AB=BC,角DCE=135度,说明:AE=ED
如图,AE⊥AB,BC⊥AB,CD⊥ED,ED=DC,求证:AE+BC=AB
已知:如图AE垂直AB,BC垂直AB,AE=AB,ED=AC,求证:ED垂直于AC
已知,如图:AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证:ED⊥AC.
如图,已知AE=AD,AB=AC,求证ED⊥BC
已知:如图,AB⊥BC,AE⊥AD,AB=AE,∠ACD=∠ADC.求证:BC=ED
如图,已知AB=AE,BC=ED,∠B=∠E,AF⊥CD,F为垂足,试说明CF=DF.
如图,在△ABC中,已知∠A等于90度,ED⊥BC于点D.AB=BD,求证:AE=ED
已知,如图,ab垂直bc,ae垂直ed,ab=ae,角acd=角adc,求证:bc=ed
如图,AB是直径,弦AE⊥CD.求证:弧BC=弧ED
如图,已知AB=AE,BC=ED,AF⊥CD于F,CF=DF.
如图,已知AB=AE,BC=ED,AC=AD.