[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)
来源:学生作业帮 编辑:作业帮 分类:综合作业 时间:2024/05/27 12:09:27
[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
[1+2+3+4+5+...+2009+2010]/[(1-1/1006)(1-1/1007)...(1-1/2009)(1-1/2010)]
=[(1+2010)*2010/2]/[(1005*1006*.*2009)/(1006*1007*.*2010)]
=[(1+2010)*2010/2]/(1005/2010)
=2021055/(1005/2010)
=4042110
=[(1+2010)*2010/2]/[(1005*1006*.*2009)/(1006*1007*.*2010)]
=[(1+2010)*2010/2]/(1005/2010)
=2021055/(1005/2010)
=4042110
计算:1+2+3+4+5+…+2009+2010/(1-1/1006)(1-1/1007)…(1-1/2009)(1-1
(1-1/2)(1/3-1)(1-1/4)(1/5-1)``````(1/2009)(11/2010)
(-1)+-2+(-3)+4+(-5)+...+(-2009)+2010
(1-1/2+1/3-1/4...+1/2007-1/2008)÷(1/1005+1/1006+1/1007+...+1
|1/2-1|+|1/3-1/2|+1/4-1/3|+...|1/2009-1/2008|+|1/2010-1/2009
计算:|1/3-1/2|+|1/4-3/1|+|1/5-1/4|+.+|1/2010-1/2009|
|1/3+(-1/2)|+|1/4+(-1/3)|+|1/5+(-1/4)|+……+|1/2010+(-1/2009)|
计算|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+...+|1/2010-1/2009|.
1/1×2+1/2×3+1/4×5+……+1/2009×2010
(-1*1/2) (-1/2*1/3) (-1/3*1/4) .(-1/2009*1/2010) (-1/2010*1/
|1/2011-1/2010|+|1/2011-1/2009|+|1/2009-1/2008|+...+|1/3-1/2
计算(1-1/2)^2*(1-1/3)^2*(1-1/4)^2*...*(1-1/2009)^2*(1-1/2010)^