y=sin2x+cos2x=√2*sin(2x+45°)
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
求函数y=[sin2x+sin(2x+π/3)]/[cos2x +cos(2x+π/3)]的最小正周期
要得到函数y=2cos(x+π/6)sin(π/3-x)-1的图像只需将函数 y=1/2sin2x+√3/2cos2x
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
函数,Y=根号2*sin2x*cos2x
函数y=log1/2(sin2x+cos2x)
两个个数学证明题1.证明:cos2x+sin2x=√2sin(sin2x+π/4)2.证明:αsinαx+cosαx=√
函数y=(cos2x+sin2x)/(cos2x-sin2x
已知函数f(x)=2 sin2x cos2x怎么变成f(x)=2 √2sin(2x pai
(SIN2X)^2+SIN2X+COS2X=1求角X
已知sin^2x+sin2x*sinx+cos2x=1,x属于(0,派/2),求tan2x
已知函数f(x)=(sin2x+cos2x)²-2sin²2x