化简cos2α/tan(π/4+α)
化简:sin2α/(1-cos2α)-1/tanα=
(1)已知tan(π/4+α)=2,求tanα,sin2α+sin^2α+cos2α
tan(α+π/4)=2,则cos2α+3sin^2α+tan2α=?
已知sin2α=a,cos2α=b,求tan(α+π/4)的值.
tan(π/4+α)=2010,那么1/cos2α+tan2α=
已知tan[α+π/4]=2,求cos2α+3sin²α的值
已知sin2α=a,cos2α=b,求tan(α+π/4)的值
已知sin2α=a cos2α=b 求 tan(α+π/4)
已知sin2α=a,cos2α=b,则tan[(π/4+α]等于?
Cos2α+cos2β+cos2γ=1 求u=tanαtanβtanγ的最小值
已知tan(π/4-α)=-1/2,则cos2α的值为?
sin2(-α)+tan(2π+α)cos2(π+α)-sin(2π-α)cos(π+α)cos2(π+α)化简 求助各