[(2X-Y)²-Y(4X+Y)-8X]÷2X
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
「(x²+y²)-(x-y)²+2y(x-y)」÷4y,其中2x-y=18
已知2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y 过程
2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
(x+y)²-2(x²-y²)+(y-x)²
(3x-2y)²(3x-2y)²(9x²+4y²)²
x²-4y² x+2y
(x-2y)²+4x-8y+4 因式分解
数学题……555{(3x+y)(3x-y)-(x-5y)(5x-y)-(x-2y)²÷(-4x),x=-2.y