(1)20042004*20042003-20042005*20042002 (2)1又1/5+3又1/35-5又1/6
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 09:45:36
(1)20042004*20042003-20042005*20042002 (2)1又1/5+3又1/35-5又1/63+7又1/99+9又1/143+11又1/195
(3)1+/12+(1/3+2/3)+(1/4+2/4+3/4)+…+(1/50+2/50+…+49/50
(3)1+/12+(1/3+2/3)+(1/4+2/4+3/4)+…+(1/50+2/50+…+49/50
(1)20042004*20042003-20042005*20042002
=20042004*(20042004-1)-(20042004+1)*(20042004-2)
设m=20042004,则
(1)=m(m-1)-(m+1)(m-2)
=m^2-m-m^2+m+2
=2
(2)1又1/5+3又1/35+5又1/63+7又1/99+9又1/143+11又1/195
=1+1/5+3+1/35+5+1/63+7+1/99+9+1/193+11+1/195
=1+3+5+7+9+11+1/5+1/2(1/7-1/9)+1/2(1/9-1/11)+1/2(1/11-1/13)+1/2(1/13-1/15)
=26+1/5+1/2(1/7-1/15)
=26又5/21
=20042004*(20042004-1)-(20042004+1)*(20042004-2)
设m=20042004,则
(1)=m(m-1)-(m+1)(m-2)
=m^2-m-m^2+m+2
=2
(2)1又1/5+3又1/35+5又1/63+7又1/99+9又1/143+11又1/195
=1+1/5+3+1/35+5+1/63+7+1/99+9+1/193+11+1/195
=1+3+5+7+9+11+1/5+1/2(1/7-1/9)+1/2(1/9-1/11)+1/2(1/11-1/13)+1/2(1/13-1/15)
=26+1/5+1/2(1/7-1/15)
=26又5/21
简算:6又3/11/(1又5/7*1.48)*2.96/2又1/11/1又1/6
(-2000又5/6)+(-1999又2/3)-(-4000又3/4)-(+1又1/2)
(-2005又5/6)+(-2004又2/3)+4010又2/3+(-1又1/2)
计算3又3/4-8又1/6-(2又1/2)-1又5/6.
-2006又5/6+(-1999又2/3)+4000又3/4+(-1又1/2)
-5又1/3+2又11/12-16又1/4-3又5/6
(-1000又2/3)+(-999又5/6)+2000又3/4+(-1又1/2)
3又(1/3) +5又(2/4) +7又(3/5) +9又(4/6) 分之 1又(2/3)+ 2又(3/4)+ 3又(4
1又3/1+2又15/2+3又35/2+4又63/2+5又99/2+6又143/2=?
1又2/3+2又2/15+3又2/35+4又2/63+5又2/99+6又2/143
找规律填空 1又1/4、3又2/9、5又3/16、7又5/25、9又8/36、11又13/49、( )
16-|-7又2分之1|-(-3又3分之2+11又6分之5)-(-3又2分之1+2又4分之1)