y=4sin(x-π/4)cos(x+π/4)怎么化简啊!
求函数y=sin^4x+cos^4x,x(0,π/6)的最小值
y=sin(-3x) =-sin3x y=cos(3x+π\4) =cos(π/2+3x-π/4) =-sin(3x-π
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
函数y=【cos(3x+π/4)-sin(3x+π/4)】/[cos(3x+π/4)+sin(3x+π/4)]的定义域,
y=sin(2x-π/4)+cos(3x+π/3)的导数
y=sin^4x/4+cos^4x的导数怎么求?
y=sin^4x +cos^4x怎么求导数
y=sin^4x+cos^4x怎么求导数
MATLAB画图,y=sin(x)*(cos(x)-1)/((2*sin(x.^2)+4*cos(x)).^0.5)-(
y=sin^2x-3sinxcosx+4cos^2x是否等于y=sin^2x+cos^2x+3cos^2x-3/2*si
求y=sin(x-π/4)cos(x+π/4),x属于[0,π/4]的反函数
y=2√3sin²(x+π/4)+2cos²x-√3怎么化成y=Asin(wx+φ)的形式