转置法则的证明如何证明 (ABCD)^T= D^T * C ^T *B^T *A^T 我可以想象出来 不过想问一个用数学

T=[(b/a)+(d/c)] 用A*表示n阶方阵的伴随矩阵,证明（A*）^T=(A^T)* Mary and Linda___here now.A.aren't B.don't C.isn't D.doesn't 设A,B均为N阶方阵,满足AA(T)=E,B(T)B=E.|A|+|B|=0.证明:|A+B|=0.A(T)为A的转置. 高一函数题：证明如果f(t)=t/（1+t),g(t)=t/(1-t),证明：f(t) - g(t) = -2g(t&s 证明：若向量组a=（a1,a2,a3,a4）T,b=（b1,b2,b3,b4）T,c=（c1,c2,c3,c4）T 设A和B都是8*3型矩阵,证明:|AA^T+BB^T|=0 数学式子证明(导数)证明(lnt*(t+1))/(t-1)>2t>1 They ( )have a bike.A.doesn't B.don't C.aren't D.not C语言,这里的 t=a; a=b; b=t; } if(a>b) { t=a; a=c; c=t; } if(b>c) Alice __any jam for cake.a.doesn't b.don't c.needn't d.doesn Mary _______late for class.A：isn't.B：doesn't.C：doesn't be.D：