设原价为X 3/5X=237 X=237*5/3 X=395
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
设f(x)={x+3,x>10,f(x+5),x
设函数f(x)={x-3(x≥10) f(f(x+5))(x
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
设f(x)=-5x^3+2x+1 零点区间为
设x²-x=-1,则3x^4-5x³+8x²-5x+1等于?
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
设函数f(x)=min{4x-x^2,-x,2x-3},则f(x)的最小值为
设f(x)=(2x+5)^2*(3x-1)^4,求f'(x)
方程(x-1/x-2)-(x-3/x-4)=(x-2/x-3)-(x-4/x-5)解为x=7/2,(1/x-7)-(1/
设全集为R,集合M={x|2x>x+3},N={x|-1
设总体X概率密度为f(x)=3/2 *x^2,│x│