设数列｛an},{bn}满足；a1=4 a2=5/2,an+1=an+bn/2,bn+1=2anbn/an+bn 用数列

数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1 已知数列{an}、{bn}满足:a1=1/4,an+bn=1,bn+1=bn/1-an^2 （1）求{an}的通项公式 数列an中,a1=3,an=(3an-1-2)/an-1,数列bn满足bn=an-2/1-an,证明bn是等比数列 2. 数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1且{bn}是以公比为q的等比数列 急 设A1=2,A2=4,数列Bn满足：Bn=A(n+1)-An,B(n+1)=2Bn +2 急 设A1=2,A2=4,数列BN满足：Bn=A(n+1)-An,B(n+1)=2Bn+2 设a1=2,a2=4,数列｛bn｝满足：bn=a(n+1)-an,b(n+1)=2bn+2. 设A1=2,A2=4,数列{Bn}满足:Bn=A(n+1) –An,B(n+1)=2Bn+2. 已知数列{an}满足a1=1,a2=2,an+2=(an+an+1)/2,n∈N*.令bn=an+1-an,证明{bn} 数列{An}{Bn}满足下列条件：A1=0,A2=1,An+2=An+An+1/2,Bn=An+1-An 一道数学数列题设两个数列{An},{Bn}满足Bn=（A1+A2+A3+……+nAn)/(1+2+3+……+),若{Bn 已知数列{an}{bn}满足a1=1,a2=3,b(n+1)/bn=2,bn=a(n+1)-an,(n∈正整数),求数列