(1+x)(x-1/x²+x-1-x/x的3次方-x)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/15 08:42:31
(1+x)(x-1/x²+x-1-x/x的3次方-x)
3x-6/x²-4÷(x+2/x²+4x+4) -2
3x-6/x²-4÷(x+2/x²+4x+4) -2
(1+x)(x-1/x²+x-1-x/x的3次方-x)
=(1+x)(x-1/x²+x-1)-(1+x)(1-x)/x的3次方-x)
=(1+x)(x-1/x(x+1)-(1+x)(1-x)/x(x+1)(x-1)
=(x-1)/x+1/x=x/x=1
3x-6/x²-4÷(x+2/x²+4x+4) -2
=3(x-2)/(x+2)(x-2)÷(x+2/(x+2)² -2
=3/(x+2)÷1/(x+2)-2
=3-2=1
=(1+x)(x-1/x²+x-1)-(1+x)(1-x)/x的3次方-x)
=(1+x)(x-1/x(x+1)-(1+x)(1-x)/x(x+1)(x-1)
=(x-1)/x+1/x=x/x=1
3x-6/x²-4÷(x+2/x²+4x+4) -2
=3(x-2)/(x+2)(x-2)÷(x+2/(x+2)² -2
=3/(x+2)÷1/(x+2)-2
=3-2=1
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