若lim(n→∞) [(3n^2+2/n+1)-an+b]=5,则a/b=多少?
lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b
已知:lim (n→∞) [(n^2+n)/(n+1)-an-b]=1 ,求a,b的值
lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
lim(n趋于无穷大)(5n^2+3n)/(an^2+b)=多少
已知lim[(an^2+5n-2)/(3n+1)-n]=b,求a,b的值
若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b
lim(n2+2n+2)/(n+1)-an)=b,求a,b
a,b为常数.lim(n->无穷)an^2+bn+2/2n-1=3 求a,b
已知lim n→无穷 (an^2+bn+5)/(3n-2)=2,求a,b的值
若极限lim((3n^2+4)/(n+2)-an+b)=6,则a=_,b=_
大一高数证明题:若an>0,且lim(n→∞)a(n+1)/a(n)=a,则lim(an^(1/n))=a
若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b=