log4 (x+3)+log(1/4) (x-3)=log(1/4) (x-1)+log4 (2x+1)的解集,
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/30 20:17:56
log4 (x+3)+log(1/4) (x-3)=log(1/4) (x-1)+log4 (2x+1)的解集,
log4(x+3)+log(1/4)(x-3)=log(1/4)(x-1)+log4(2x+1)
log4(x+3)-log4(2x+1)=log(1/4)(x-1)-log(1/4)(x-3)
log4(x+3)/(2x+1)=log(1/4)(x-1)/(x-3)
log4(x+3)/(2x+1)=log4(x-3)/(x-1)
(x+3)/(2x+1)=(x-3)/(x-1)
(2x+2)(x-3)=(x+3)(x-1)
2x2-6x+2x-6=x2+2x-3
x2-6x-3=0
x=3±2√3
log4(x+3)-log4(2x+1)=log(1/4)(x-1)-log(1/4)(x-3)
log4(x+3)/(2x+1)=log(1/4)(x-1)/(x-3)
log4(x+3)/(2x+1)=log4(x-3)/(x-1)
(x+3)/(2x+1)=(x-3)/(x-1)
(2x+2)(x-3)=(x+3)(x-1)
2x2-6x+2x-6=x2+2x-3
x2-6x-3=0
x=3±2√3
解方程log4 x+1/log4 x=10/3
解方程 log4 (3x-1)=log4 (x-1)+log4 (3+x)
有关log的数学题①log2(2X+3)=0②log5(X)-1/3log5(8)=0③log2(X)+log4(X)=
log4(3x-1)-log4(3+x)=log4(x-1)
log4(x+3)+log1/4(x-3)=log1/4(x-1)+log4(2x+1),说明:
解不等式:log3/4(x+1)>log4/3(x-3)
解关于x的方程:log4(x+2)+log(x+2) =5
解关于x的方程:log4(x+2)+log(x+2) ²=5
log4 (3-x/1-x)=log1/4 (2x+1/3+x)
方程4x+2x-2=0的解是 .例6方程log4(3x-1)=log4(x-1)+log4(3+x) 的解是
解方程log4(3x+1)=log4x+log4(3+x)
y=log4(3x+1)+1/2log4(x+1),x∈【0,1】的值域