kπ-2π/3
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1
2kπ+π
请问,第一题的范围是(2kπ+π,2kπ+3π/2)k∈Z
1k、2k、3k是什么意思
K-1+K+2+K/3+K*3=2001
请问1^k+2^k+3^k+.+n^k=?
3×k×k-2k-1=-1.k等于
1^k+2^k+3^k+.+n^k 有无表达式
2/3π+2kπ与5/3π+2kπ的交集
化简sin(kπ + 2/3π )× cos(kπ -π/6 )
求值tan(kπ+π/6)cos(kπ-4π/3),k属于z
求证:lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1