(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/
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(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/131/17+1/19)×(1/11+1/13+1/17)
递等式运算
递等式运算
令1+1/11+1/13+1/17+1/19=a;1+1/11+1/13+1/17=b;
则有:
b×(a-1)-a×(b-1)
=ab-b-ab+a
=a-b;
=1/19;
这也是递等式运算,只不过用a,b代替复杂的算式而已,你不信明天等着老师讲,你们老师肯定也是这样写的
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
再问: 真的话 就谢谢你啦
则有:
b×(a-1)-a×(b-1)
=ab-b-ab+a
=a-b;
=1/19;
这也是递等式运算,只不过用a,b代替复杂的算式而已,你不信明天等着老师讲,你们老师肯定也是这样写的
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,
再问: 真的话 就谢谢你啦
1计算(1+1/11+1/13+1/17)(1/11+1/13+1/17+1/19)-(1+1/11+1/13+1/17
(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/13+1/17+1
(1+11/1+13/1+17/1)×(11/1+13/1+17/1+19/1)-(1+11/1+13/1+17/1+1
(1+1/11+1/13+1/17)乘以(1/11+1/13+1/17+1/19)-(1+1/11+1/13+1/17+
简便计算:(1+1/11+1/13+1/17)*(1/11+1/13+1/17+1/19)-(1+1/11+1/13+1
(1+1/11+1/13+1/17)×(1/11+1/13+1/17+1/19)-(1+1/11+1/13+1/17+1
(1+1/11+1/13+1/17)x(1/11+1/13+1/17+1/19)-((1+1/11+1/13+1/17+
(1/11-1/13)+(1/13-1/15)+(1/15-1/17)+(1/17_1/19)+(1/19-1/21)+
简算:1/11×13 +1/13×15 +1/15×17 +1/17×19
有理数得乘法(1+1分之11 +1分之13+1分之17)乘(11分之1+13分之1+17分之1+19分之1)-(1+11
简便计算(要过程):1/11×13+1/13×15+1/15×17+1/17×19+1/19×21=( )
9×11/1+11×13/1+13×15/1+15×17/1+17×19/1)÷(9/1减19/1)