[(x+2y)²-(x+y)(x-y)-4y²]÷2y
(x-2y)²+(2x-4y)(x+y)+(x+y)²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
(x-y)的四次方(x-y)-2(x-y)²(y-x)³等于?
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]
已知2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值?
{(x-y)²+(x+y)(x-y)}÷2x
(3x-y)²-2x(4x-5y)-(x+2y)²
2.(x+y)²(x-y)²-(x-y)(x+y)(x²+y²)
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
已知x²-y²=10,求[(x+y)³-2y(x+y)²-4(x+y)]÷(x+