作业帮急 求 （log3 2+log9 2）-（log4 3+log8 3）
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/13 06:06:39
急 求 （log3 2+log9 2）-（log4 3+log8 3）
求 （log3 2+log9 2）-（log4 3+log8 3）
求 （log3 2+log9 2）-（log4 3+log8 3）
答：
（log3 2+log9 2）-（log4 3+log8 3）
=log3(2)+log9(2)-log4(3)-log8(3)
=log3(2)+log3(2)/log3(9)-log3(3)/log3(4)-log3(3)/log3(8)
=log3(2)+(1/2)log3(2)-1/[2log3(2)]-1/[3log3(2)]
=(3/2)log3(2)-(5/6)/log3(2)
怀疑中间不是减号,而是乘号：
（log3 2+log9 2）×（log4 3+log8 3）
=[log3(2)+log9(2)]×[log4(3)+log8(3)]
=[log3(2)+log3(2)/log3(9)]×[log3(3)/log3(4)+og3(3)/log3(8)]
=[log3(2)+(1/2)log3(2)]×{1/[2log3(2)]+1/[3log3(2)]}
=[(3/2)log3(2)]×[(5/6)/log3(2)]
=5/4
（log3 2+log9 2）-（log4 3+log8 3）
=log3(2)+log9(2)-log4(3)-log8(3)
=log3(2)+log3(2)/log3(9)-log3(3)/log3(4)-log3(3)/log3(8)
=log3(2)+(1/2)log3(2)-1/[2log3(2)]-1/[3log3(2)]
=(3/2)log3(2)-(5/6)/log3(2)
怀疑中间不是减号,而是乘号：
（log3 2+log9 2）×（log4 3+log8 3）
=[log3(2)+log9(2)]×[log4(3)+log8(3)]
=[log3(2)+log3(2)/log3(9)]×[log3(3)/log3(4)+og3(3)/log3(8)]
=[log3(2)+(1/2)log3(2)]×{1/[2log3(2)]+1/[3log3(2)]}
=[(3/2)log3(2)]×[(5/6)/log3(2)]
=5/4
【（log4）^3+.（log8）^3】【.（log3）^2+.（log9）^2】=几啊
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4^3+log8^3)(log3^2+log9^2)
求值(log4(3)+log8(3))×(log3(2)+log9(2))
求值(log3(2)+log9(2))*(log4(3)+log8(3))
(log3 2+log9 2)*(log4 3+log8 3)求值
(log3^2 + log9^4)×(log4^3 + log8^3)
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
（log3 2）+log9 2)*(log4 3+log8 3)+(log3 3^1/2)^2+ln根号e-lg1
（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2
计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log2
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9）