数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5使得{(an+y)/3^n}为等差数列的实
数列an满足递推式an=3an-1+3^n-1,n大于等于2,其中a1=5,则使得{an+入、3……n}为等差数列的实数
数列{an}满足递推式an=3a(n-1)+3^n-1(n>=2),又a1=5,求数列{an}的通项公式
已知数列{an}满足a1=3 an*a(n-1)=2a(n-1)-1,求证数列{1/(an-1)}是等差数列,并求出数列
数列an满足an+1=3an+n,是否存在适当的a1,使{an}是等差数列,说明理由
已知数列{an}满足a1=1,a(n+1)=3an+2(n属于N) 1.求证数列{an+1}是等比数列 2.求{an}的
已知数列{an}满足a1=4,an+1=an+p.3^n+1(n属于N+,P为常数),a1,a2+6,a3成等差数列.
已知数列{an}满足an+an+1=2n+1(n∈N*),求证:数列{an}为等差数列的充要条件是a1=1.
数列{an}满足a1=33,a(n+1)-an=2n,则an/n的最小值为_
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an
已知数列{an}满足a1=1,an=(an-1)/3an-1+1,(n>=2,n属于N*),求数列{an}的通项公式
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知等差数列{an}满足a(n+1)=an+3n+2,且a1=2,求an.