A2=A,B2=B,AB+BA=O证明AB=O
证明:a3+b3=(a+b)(a2-ab+b2)
已知a2 2ab b2=O求a(a 4b)-(a 2b)(a-2b)
已知A=a2-2ba,B=-3ab+b2,求3A-2B
若非零实数a、b满足4a2+b2=4ab,则ba等于( )
已知a、b≠0,且3a2+ab-2b2=0,则ab−ba−a
若实数a,b满足a2+a-1=0,b2+b-1=0,则ab+ba
已知a2+b2=6ab且a>b>0,则a+ba−b
已知实数a.b满足下列关系a2-5a+2=0,2b2-5b+1=o求(ab+1)/b的值
ab(a2+b2)x2-(a+b2)x+(a2-b2)/(a2+b2)=0
3a2+ab-2b2=0,求a/b-b/a-(a2+b2)/ab (a,b不等于0)
已知a,b均为质数,且满足a2+ba=13,则ab+b2=______.
a2-b2=(a+b)(a-b) a3+b3=(a+b)(a2-ab+b2) a3-b3=(a-b)(a2+ab+b2)