∫arctanx÷(1+x^2)dx=

∫[x+e^(arctanx)/ (1+x^2) ]dx= ∫(arctanx)^2/1+X^2 dx ∫(arctanx)^3/(1+x^2)dx ∫(0 1)x(arctanx)^2dx 求不定积分∫(arctanx)/(x^2(x^2+1))dx 求积分 ∫(arctanx)/(x^2(x^2+1))dx 积分∫arctanx*x^2/(1+x^2)dx 求不定积分 ∫ x -arctanx / 1+x^2 dx 求不定积分∫x+arctanx/(1+x^2)dx ∫ (x+arctanx)/x^2 dx 求不定积分 ∫ 1/ (1+x^2)(arctanx)^2 dx 定积分∫(-1,1)arctanx/(1+x^2)dx,