lim[1+3+5+…+(2n-1)/[n(2n-1)]等于多少?

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/23 16:00:47

1+3+5+…+(2n-1) = n(2n-1+1)/2 = n^2
[1+3+5+…+(2n-1)/[n(2n-1)] = (n^2)/[n(2n-1)] = n/(2n-1) = 1/(2 - 1/n)
lim[1+3+5+…+(2n-1)/[n(2n-1)] = lim[1/(2 - 1/n)] = 1/2

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