(x+y)(x²-xy+y²)=x³+y³怎么推导的,具体点,一步一步来
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[-xy/(x-y)²]²×(y²-xy/x)³
已知x²+y²-8x+6y+25=0,求(x-y+4xy/x-y)(x+y-4xy/x+y)
X²-3XY+2Y² =(x-y)(x-2y) 中(x-2y) 是怎么算出来的?
已知xy=1,求代数式负三分之一x(xy²+y+x³y四次方)的值
(x-y)的四次方(x-y)-2(x-y)²(y-x)³等于?
x⁴+4x³y+6x²y²+4xy³+y⁴=( )
-2y³+(3xy²-x²y)-2(xy²-y³)
计算:(-7x²y)(2x²y-3xy³+xy)
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
(-x/y)²×(-y²/x)³÷(-xy的四次方)