-7+x+2x^2+6x^3+4x^4=0

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/21 17:03:29

-7+x+2x^2+6x^3+4x^4=0
没有抄错题啊，就是这个四次方程

用数学软件Solve[4 x^4 + 6 x^3 + 2 x^2 + x - 7 == 0,x]：{{x -> -(3/8) +
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/
8) + 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/
8) - 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/8) -
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}}
这是mathematica的运行结果

x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值 2x+3x+4x+5x+x+6x+7x=100 已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值 |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10), 解方程(x-2)/(x-3)-(x-3)/(x-4)=(x-5)/(x-6)-(x-6)/(x-7) 解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8) （1） x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8