如图,求x=cos^3(t)、y=sin^3(t)围成的面积.
求由摆线x=a(t-sin t),y=a(1-cos t)及x轴所围成的图形的面积(0
已知 x = e^t * cos t y = e^t *sin t 求当t= π/3时dy/dx的值
求教各位数学大神:参数方程的定义域怎么求?如:x=a*(cos(t))^3,y=a*(sin(t))^3 (a>0),(
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matlaB函数问题t = -pi:0.01:pi;x=cos(t)-sin(3*t);y=sin(t)+cos(t);
用matlab 如何作出y与t的图?y=(sin(t)-sin(t0))^2 且 cos t+t*sin t-cos t
计算星形线x=a cos^3t,y=a sin^3t的全长
我的matlab程序哪里错了? t=0:0.01:2*pi x=cos(t)^3 y=sin(t)^3 plot(x,y
设函数y=y(x)由参数方程x=cos t,y=sin t - t cos t确定,求dy/dx
设x=e'sin t,y=e'cos t,求dy/dx.
求导:x=cos^4*t,y=sin^4*t,求dy/dx
如何x(t)=cos(t)+asin(t) y(t)=sin(t)+bcos(t) expressing x(t) in