求极限.lim(x→pi/2)(secx-tanx)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/24 10:40:44
求极限.lim(x→pi/2)(secx-tanx)
“pi”=3.14 那个数学字母打不出来.pi/2在lim下面
“pi”=3.14 那个数学字母打不出来.pi/2在lim下面
lim(x→π/2) secx-tanx
=lim(x→π/2) 1/cosx-sinx/cosx
=lim(x→π/2) (1-sinx)/cosx
=lim(x→π/2) [(1-sinx)(1+sinx)]/[cosx(1+sinx)]
=lim(x→π/2) (1-sin²x)/[cosx(1+sinx)]
=lim(x→π/2) cosx/(1+sinx)
=cos(π/2)/[1+sin(π/2)]
=0/(1+1)
=0
=lim(x→π/2) 1/cosx-sinx/cosx
=lim(x→π/2) (1-sinx)/cosx
=lim(x→π/2) [(1-sinx)(1+sinx)]/[cosx(1+sinx)]
=lim(x→π/2) (1-sin²x)/[cosx(1+sinx)]
=lim(x→π/2) cosx/(1+sinx)
=cos(π/2)/[1+sin(π/2)]
=0/(1+1)
=0
lim x趋于pi/2.(sinx)^tanx 求极限
x趋近pai/2时[secx-tanx]求极限
求极限lim x→π(sin3x)/(x-π)和求极限lim x→π/2(1+cosx)secx
secx+ tanx>o -pi/2
求极限lim(x→0)(tanx-sinx)/(x-sinx)
求极限:lim(x→0)(tanx-sinx)/x^3
求lim(x→0)tanx/3x的极限
lim[sinx/(pi-x)] {x->pi} 求函数的极限
lim x→0.25派 (tanx)∧tan2x 求极限
求极限 lim(tanx)^tan2x ,x→∏/4
求极限:x→0 lim[(1+tanx)^cotx]
求极限lim.[( tanx-sinx) /(sin^2 2x)]