y=y(x),通过方程sin(x2+y)-xy=1求Dy=?

设隐函数y=y(x)由方程x^y-e^y=sin(xy)所确定,求dy 设y=y(x)由方程e^xy+sin(xy)=y确定,求dy/dx. 设y=y(x)由方程x^2-sin(xy)=2y确定,求dy/dx 设sin(x+y)=xy,求dy/dx. 设函数y=f(x)由方程sin(xy)+e^(x+y)=0确定,求dy/dx 设函数y=f(x)由方程sin(x^2+y)=xy 确定,求dy\dx （1）y-sin（Inx）求y （2）（e^x+y）-xy=0求dy y=3^sinx,求dy/dx Y=e^2x sin^3x求dy 求方程e^y=xy确定的隐函数y=y(X)导数（e^y 1,y=e^tanxcos^3x,求dy 2,函数y=y（x）由方程e^(x+y)+arctan(xy)=0确定,求dy y=x*sin(lnx) 求dy Z=x*sin xy+e^x+y或设y=(x)是由方程xy+sin x+sin y=1确定,求y” 设方程sin y +ex(x次方)-xy 2(平方)=0确定隐函数y =y (x),求dy /dx