化简(2m/m2-4-1/m-2)÷(1-1/m+2)
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化简(2m/m2-4-1/m-2)÷(1-1/m+2)
化简 [2m/(m2-4)-1/(m-2)]÷[1-1/(m+2)]
解,得:
==[2m/(m+2)(m-2)-1/(m-2)]÷[(m+1)/(m+2)]
==[2m/(m+2)(m-2)]÷[(m+1)/(m+2)]-[1/(m-2)]÷[(m+1)/(m+2)]
==[2m/(m+2)(m+2)(m-2)(m+1)]-[1/(m-2)(m+1)(m+2)]
==[2m-(m+2)]/[(m+2)(m+2)(m-2)(m+1)]
==(m+2)/[(m+2)(m+2)(m-2)(m+1)]
==1/[(m+2)(m-2)(m+1)]
==1/[m2-4)(m+1)]
解,得:
==[2m/(m+2)(m-2)-1/(m-2)]÷[(m+1)/(m+2)]
==[2m/(m+2)(m-2)]÷[(m+1)/(m+2)]-[1/(m-2)]÷[(m+1)/(m+2)]
==[2m/(m+2)(m+2)(m-2)(m+1)]-[1/(m-2)(m+1)(m+2)]
==[2m-(m+2)]/[(m+2)(m+2)(m-2)(m+1)]
==(m+2)/[(m+2)(m+2)(m-2)(m+1)]
==1/[(m+2)(m-2)(m+1)]
==1/[m2-4)(m+1)]
化简(2m/m2-4-1/m-2)÷(1-1/m+2)
m2(m+4)+2m(m2-1)-3m(m2+m-1),其中m=25.
化简﹙2m/m2-4-1/m-2﹚÷﹙1-1/m+2﹚
直线(2m2+m-3)x+(m2-m)y=4m-1与直线2x-3y-5=0
化简,求值:m2-1/m2-2m+1÷(m-1-m+1/m-1),其中m=√3
如果m-m/1则m2次加m等于( ),2m2次加2m-1等于( )
(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3
1/(m2-m)+(m-5)/(2m2-2)
化简:2[(m-1)m+m(m+1)][(m-1)m-m(m+1)]
已知m属于R,复数Z=(m2+m-2)+(m2+2m-3)i,当m为何值时4).Z=1/2+4i
若方程(2m2+m-3)x+(m2-m)y-4m+1=0表示一条直线,则实数m满足( )
若方程(2m2+m-3)x+(m2-m)y-4m+1=0表示一条直线,则实数m满足